If a fifty element array is in order, the sort would have done 50 comparisons and would have stopped. The sort algorithm is able to quit early. if the data is in order, there is no swap and there is no second loop. Ni dung bi vit bao gm cc phn sau: Lu : Bi vit ch m t cho. bi vit ny Nguyn Vn Hiu xin gii thiu ti cc bn thut ton sp xp bubble sort.
BUBBLE SORT CODE IN C SERIES
If a swap takes place, you do the sort again. y l mt bi vit trong series cc thut ton sp xp c minh ha code s dng ngn ng lp trnh C++. Slide along the array, comparing position(i) to position(i+1). An array of 50 elements, already sorted will do 50*49 comparisons. Even if the array was already in order, the sort cannot stop. At then end of the inner loop, the lowest element is in position 1, then it begins with position 2, comparing it to the remaining elements, and doing an exchange. Bubble sort in C is the most straightforward sorting algorithm called a sinking sort, and It works by repeatedly moving the largest elements to the highest. The exchange sort on the outer loop checks each entry in the table against the first element, exchanging when necessary. Printf("Please enter the value of the elements: \n") Īll I follow from the above examples is an implementation of the exchange sort. Void swap (int arr, int num, int number) īool checkBigger (int arr, int num, int number) (It also must be arranged in ascending order).
The problem is the program does not sort the array in properly. I am not sure what is the problem or in which function the problem is in.
The program I"m trying to finish is a program using the bubble sort algorithm.
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